How much are the number marbles each one has?
January 24th, 2010 | by admin |Abel, Benny and Charles have 249 marbles. Abel has 20 marbles more than Benny. Twice Charles numbers of marbles is 6 more than the sum of Abel and Benny’s marbles?
Marbles of Benny—b:
a + b + c = 249
b = 249 – a – c
Marbles of Abel—a
a = 20 + 249 – a – c
a = 269- a – c
2a = 269 – c
a = 269/2 – 1/2c
Marbles of Benny—b:
= 249 – (269/2 – 1/2c) – c
= 498/2 – 269/2 + 1/2c – 2/2c
= 229/2 – 1/2c
Marbles of Charles—c:
2c = 6 + 229/2 – 1/2c + 269/2 – 1/2c
4c = 12 + 229 – c + 269 – c
6c = 510
c = 85
Marbles of Benny:
= 229/2 – 1/2(85)
= 229/2 – 85/2
= 144/2 or 72
Marbles of Abel:
= 269/2 – 1/2(85)
= 269/2 – 85/2
= 184/2 or 92
Answer: marbles: Abel has 92, Benny has 72 & Charles has 85.
2 Responses to “How much are the number marbles each one has?”
By Hapsa!!!!!!! on Jan 24, 2010 | Reply
Abel – 20 marbles
Benny – less than Abel
Charles – 26 marbles – I think.
Benny has less than abel, so ny number I guess.
References :
By Jun Agruda on Jan 24, 2010 | Reply
Marbles of Benny—b:
a + b + c = 249
b = 249 – a – c
Marbles of Abel—a
a = 20 + 249 – a – c
a = 269- a – c
2a = 269 – c
a = 269/2 – 1/2c
Marbles of Benny—b:
= 249 – (269/2 – 1/2c) – c
= 498/2 – 269/2 + 1/2c – 2/2c
= 229/2 – 1/2c
Marbles of Charles—c:
2c = 6 + 229/2 – 1/2c + 269/2 – 1/2c
4c = 12 + 229 – c + 269 – c
6c = 510
c = 85
Marbles of Benny:
= 229/2 – 1/2(85)
= 229/2 – 85/2
= 144/2 or 72
Marbles of Abel:
= 269/2 – 1/2(85)
= 269/2 – 85/2
= 184/2 or 92
Answer: marbles: Abel has 92, Benny has 72 & Charles has 85.
References :